z^2-2(1+i)z+2i=0

Solution for z^2-2(1+i)z+2i=0 equation:

Simplifying
z2 + -2(1 + i) * z + 2i = 0

Reorder the terms for easier multiplication:
z2 + -2z(1 + i) + 2i = 0
z2 + (1 * -2z + i * -2z) + 2i = 0

Reorder the terms:
z2 + (-2iz + -2z) + 2i = 0
z2 + (-2iz + -2z) + 2i = 0

Reorder the terms:
2i + -2iz + -2z + z2 = 0

Solving
2i + -2iz + -2z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '2z' to each side of the equation.
2i + -2iz + -2z + 2z + z2 = 0 + 2z

Combine like terms: -2z + 2z = 0
2i + -2iz + 0 + z2 = 0 + 2z
2i + -2iz + z2 = 0 + 2z
Remove the zero:
2i + -2iz + z2 = 2z

Add '-1z2' to each side of the equation.
2i + -2iz + z2 + -1z2 = 2z + -1z2

Combine like terms: z2 + -1z2 = 0
2i + -2iz + 0 = 2z + -1z2
2i + -2iz = 2z + -1z2

Reorder the terms:
2i + -2iz + -2z + z2 = 2z + -2z + -1z2 + z2

Combine like terms: 2z + -2z = 0
2i + -2iz + -2z + z2 = 0 + -1z2 + z2
2i + -2iz + -2z + z2 = -1z2 + z2

Combine like terms: -1z2 + z2 = 0
2i + -2iz + -2z + z2 = 0

The solution to this equation could not be determined.